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Solutions to problems in .NET Integration Code 128A in .NET Solutions to problems

Solutions to problems generate, create code 128c none with .net projects .NET Framework columns in each ca visual .net Code 128B se, are full of contradictions; so we reject the hypothesis that R1 was set at position 1 at the encipherment of the indicators. If we now encipher the same pairs at settings (3 and 4) we get Table S.

9, and these pairings are completely consistent. Any other combination of chain alignment and setting of R1 would lead to contradiction. We therefore conclude that R1 was set at position 3 at the start of the encipherment of the indicators at the ground setting.

If this is so, the pairings in the composite re ector are (0, 5), (1, 3), (2, 8), (4, 7), and (6, 9). Table S.9.

Pair (5, 7) (1, 9) (8, 0) (4, 2) (6, 3) Setting 3 (6, 9) (4, 7) (3, 1) (8, 2) (5, 0) Pair (5, 7) (1, 0) (8, 2) (4, 3) (6, 9) Setting 4 (9, 6) (2, 8) (0, 5) (1, 3) (7, 4). 10 . 10.1 (Hagelin mess age) Since the cage is (0, 5, 5, 5, 5, 5) the only keys that can occur are 0, 5, 10, 15, 20 and 25 with relative frequencies 1, 5, 10, 10, 5 and 1. We write down six lines showing what the plaintext would be if the key value were 0, 5, 10, 15, 20 or 25 at each position of the text using the Hagelin decipherment rule: plaintext letter key cipher letter.

. The cipher and six lines corresponding to the six keys are shown in Table S.10. Table S.10 Cipher Key 0 Key Key Key Key Key 5 10` 15 20 25. CBZPC YZBLY DEGQD IJLVI NOQAN STVFS ^YAK^ CJXWY YRDEC DWIJH IBNOM NGSTR SL^YW ^UCDB CXSHN YDITN DINYS INSD^ NS^IC S^CNH ^CHSM IQUSR SKGIJ ^PLNO CUQST HZV^Y MEACD RJFHI solutions to problems The solution is SOLVING THIS IS EASY The numbers of cor rect plaintext letters appearing in the six rows are seen to be 0, 3, 5, 8, 4, and 0 These agree fairly well with what we would expect from the theoretical key distribution which predicts that, in a suf ciently long text, the ratios should be 1 : 5 : 10 : 10 : 5 : 1. 10.2 (Hagelin cages) All but cages (b) and (e) generate all key values (mod 26).

Cage (b) fails to generate key values 13 and 14. Cage (e) fails to generate key values 4, 12, 15 and 23. Note that if an unoverlapped cage which uses 27 lugs fails to generate key value N it must also fail to generate key value (27 N) since the kicks add up to 27 and by reversing the pins on the wheels a key value of N becomes a key value of (27 N).

10.3 (Overlapped Hagelin cage producing key value 17) There is unfortunately no short cut to nding these representations although we can reduce the number of pin combinations that we need to examine by noting that one, and only one, of the two big kicks (11, 9) will be required, since together they give 18 (ie 11 9 2), and the other four (7, 5, 3 and 1) only add up to 16, and overlaps would reduce this further. We need therefore consider only 32 of the 64 possible pin combinations.

The six combinations which produce key value 17 are: OXXOXO OXXOXX OXXXOO XOOXOX XOOXXO XOOXXX which gives (9 which gives (9 7 3 which gives (9 7 which gives (11 which gives (11 which gives (11 5 3 7 3) (2) 1) (2 1) 5) (2 2) 5 1) (0) 5 3) (2) 1) (2 1) 17; 17; 17; 17; 17; 17.. Solutions to problems 11 . 11.1 (Pin-setting visual .net code-128c errors in the Hagelin and SZ42) (1) Every 23rd cipher letter would be different in the two cipher texts.

In an unoverlapped machine the amount of the difference would be the kick on the 23-wheel. In an overlapped machine the difference might be one of two or more values, depending upon how the 23-wheel was overlapped with the other wheels. (2) Every 31st cipher letter would be different in the two cipher texts, the difference being seen in the 2nd bit of the 5-bit ITA characters.

(3) Since the 61-wheel controls the 37-wheel, which in turn controls all the wheels of set C, the 37-wheel, and hence the wheels of set C, would get steadily more and more out of step with their correct positions and so the cipher texts would differ, apart possibly from an occasional accidental agreement, from some point in the rst 61 letters of the text..
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